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What is the exact value of the expression sqrt(32) + sqrt(75) - sqrt(98)? Simplify Completely.
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The approach is to find squares in each of the components. As an example 32 = 16x2, where 16 is a square of 4. Therefore, \[\sqrt{32}=\sqrt{16\times2}=\sqrt{16}\sqrt{2}=4\sqrt{2}\] A similar approach should be taken for each of the other numbers. 75 = 25x3 and 98 = 49x2. Using the method above, \[\sqrt{75}=\sqrt{25*3}=\sqrt{25}\sqrt{3}=5\sqrt{3}\] \[\sqrt{98}=\sqrt{49*2}=\sqrt{49}\sqrt{2}=7\sqrt{2}\] Putting it all together now: \[\sqrt{32}+\sqrt{75}-\sqrt{98}=4\sqrt{2}+5\sqrt{3}-7\sqrt{2}\] combining common terms for final answer: \[\sqrt{32}+\sqrt{75}-\sqrt{98}=5\sqrt{3}-3\sqrt{2}\]
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