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How do you find all the solutions for x in the equation (x^2+6)^2/3=16
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raise both sides to the 3/2 power
you will get \[x^2+6=16^\frac{3}{2}\]
square root of 16 is 4 4^3=64 so we have \[x^2+6=64\]
i will leave the rest to you
let me know if you run into trouble
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actually i think we can say plus or minus
\[x^2+6=\pm 64\]
but you should check both solutions to make sure they are actually solutions
\[(x^{2}+6)^{2/3}=16\] this is the actual equation, sorry
ok that is what i thought it was lol
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