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Solve. 64^3x=32y=2
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\[64^3x+32y=2\]????? solve for x or y????
x=1/131072 y=1/16
thanks thangie
\[64^3x=2-32y\] \[x=\frac{2-32y}{64^3}=\frac{\cancel2(1-16y)}{\cancel2(64*64*32)}=\frac{1-6y}{131072}\] \[32y=2-64^3x\] \[y=\frac{2-64^3x}{32}=\frac{\cancel2(1-131072x)}{\cancel2(16)}=\frac{1}{16}-\frac{131072x}{16}=\frac{1}{16}-8192x\]
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