Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Solve. 64^3x=32y=2

OpenStudy (anonymous):

\[64^3x+32y=2\]????? solve for x or y????

OpenStudy (anonymous):

x=1/131072 y=1/16

OpenStudy (anonymous):

thanks thangie

OpenStudy (anonymous):

\[64^3x=2-32y\] \[x=\frac{2-32y}{64^3}=\frac{\cancel2(1-16y)}{\cancel2(64*64*32)}=\frac{1-6y}{131072}\] \[32y=2-64^3x\] \[y=\frac{2-64^3x}{32}=\frac{\cancel2(1-131072x)}{\cancel2(16)}=\frac{1}{16}-\frac{131072x}{16}=\frac{1}{16}-8192x\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!