Question

simplfy if possible: (x^2+9x+20/4x) / (5x+25/2x^2)

Answer 1

Have you multiplied by the reciprocal yet?

Answer 2

no not yet

Answer 3

i confused myself...so i need to know what to do after i do the reciprocal

Answer 4

Factor the x^2+9x+20 out. Remember how to do this?

Answer 5

yes i remeber that and i came up with (x+5) (x+4)

Answer 6

4 times 5 is 20, 4 plus 5 is 9. You get (x+4)(x+5)

Answer 7

All right, and then on the denominator is 5x+25. What can you do with that to cancel out something from (x+4)(x+5)?

Answer 8

\[\frac{\frac{x^2+9x+20}{4x}}{\frac{5x+25}{2x^2}}\]
\[\frac{x^2+9x+20}{4x}*\frac{2x^2}{5x+25}\]
\[\frac{(x+4)(x+5)}{4x}*\frac{2x^2}{5(x+5)}\]
\[\frac{x(x+4)}{2*5}\]

\[\frac{x^2+4x}{10}\]

Answer 9

That must have been a pain to type

Answer 10

thanks everyone for the help!!

Answer 11

np