Question

does anyone knows the craimer's rule here??

Answer 1

for which part?

Answer 2

first part

Answer 3

y = na-mc /ad-bc

Answer 4

a 1 x + b 1 y = c 1 (1)

a 2 x + b 2 y = c 2 (2) solve that in craimers rule..

Answer 5

thats better :)

Answer 6

can you solve it??

Answer 7

\[x = \frac{c2b1-c1b2}{a2b1 - a1b2}\]
\[y = \frac{c2a1-c1a2}{a1b2-a2b1}\]

Answer 8

i perfer not to have so many variables the same

Answer 9

b 2 a 1 x + b 2 b 1 y = b 2 c 1 (1)
- b 1 a 2 x - b 1 b 2 y = - b 1 c 2 (2)
____________________________
b 2 a 1 x - b 1 a 2 x = b 2 c 1 - b 1 c 2

i got that by multiply equation (1) by b 2 and equation (2) by -b 1 and add the right and left hand terms

Answer 10

ax + by = n (1)

cx + dy = m (2)

\[x = \frac{mb-nd}{cb-ad}\]
\[y = \frac{ma-nc}{ad-bc}\]

Answer 11

you did fine

Answer 12

tnx..