Find the angles between o degrees and 360 degrees which satisfy the following equation : tan 5x=tan 2x
180 degees
the answer behind says : 60,120,180,240 and 300 degrees.
theres multiple answers
its should = 0
dont have to = 0 but for 180 or 360 both side = 0
Recall that the following property of the tangent function as a consequence of its period:\[\tan(x+90)=\tan(x)\]Thus, we can say\[\tan(5x+180n)=\tan(2x)\text{, where } n\in\mathbb Z\]Take the arctangent of both sides (remember that the arctangent function is domain-restricted for -90<x<90):\[5x+180n=2x\text{, where } n\in\mathbb Z\]Solve for x, taking note that since n is an arbitrary integer, and since integers can be either negative or positive, it is reasonable to say that -n=n.\[x=60n\text{, where } n\in\mathbb Z\]Applying the restriction, we get the set of solution values:\[x=\left\{0,60,120,180,240,300,360\right\}\]
My apologies, the first equation above should be \[\tan(x+180)=\tan(x)\]
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