Question

I need help with how to actually work this problem, not just an answer. f(x)=I 3x I +2x^2 even/odd/neither. I get odd, but when I plug it into an online algebra calculator, it spits out even. What am I doing wrong??

Answer 1

the right and left side are mirror images of each other so its an even function

Answer 2

yeah but how do you get that?

Answer 3

I don't know how to plug in an absolute value into my calculator, is it possible?

Answer 4

if its even then
f(x)=f(-x)
if its odd then
f(x)=-f(-x)

Answer 5

if u can prove f(x) is equal to f(-x) then it is an even function

Answer 6

ok so I have to plug in a positive and a negative of the same number i.e. f(2) of f(-2) into the equation and either one will come up with an even number, correct?

Answer 7

ok not necessarily even number but the SAME number

Answer 8

yes then the function is an even function. u might want to try more than 1 number tho cuz it could just be coincidence

Answer 9

yeah I've done a few and it's working out the same. The whole odd number was throwing me off. I thought the number had to be even, not the case.

Answer 10

nope just the same but i think u got it now

Answer 11

you have one even function added to another; the result is an even function

Answer 12

f(-x)= |-3x| +2(-x)^2 = |3x| +2(x)^2 = f(x)

algebraically its even as well