how can you tell what an even or odd function is?
if f(x) =f(-x) ==> the function is even , and if f(-x) = -f(x) ===> the function is odd.
so... how do you find if \[f(x)=x ^{4}-20x ^{2}\] is even or odd?
f(x) = x^4-20x^2 , f(-x) = (-x)^4 -20(-x)^2 = x^4=20x^2 ===> f(x) = f(-x) ==> f(x) is even
thank you.
the find -f(x) = -x^4+20x^2 ===> f(-x) is not wequal to -f(x) ===> f(x) is not odd
check out this video: http://www.youtube.com/watch?v=2kPSG3dCmYo might help u
f(x) = \[(-x)^{4}-20(-x)^{4}\] So because the x is to the fourth power (and square), it reverts back to x. Like, \[(-x)^2 = x^2,\] right? And \[(-x)^4 = x^4\], right? And so on. However, \[(-x)^3\] will just be \[(-x)^3\], right? So in your case, the equation (after substituting in -x for x) will just "revert" back to f(x) =\[ x^4 - 20x^2\], which is the same thing as your original function, therefore, your function is even.
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