Explain the quadratic formula and how to use it.
The quadratic formula can be used to solve.. quadratic equations. A quadratic equation is defined by: \[ax^{2}+bx+c^{2}\] In the equation the coefficient is listed as a, b and a constant c. The quadratic equation is: \[x = -b \pm \sqrt{b^2-4ac}/2a\] You just substitute in your coefficients and simplify the answer. You will get two answers. :) For example: x^2 +10x + 9 a = 1 b = 3 c = 9 \[x = -b \pm \sqrt{b^2-4ac}/2a\] -10 +/- sqrt(10^2-4x1x9)/2x1 -10 +/- sqrt(100-36)/2x1 -10 +/- 8 /2 -10+ 8 /2 = -2/2 = -1 -10 - 8 /2 = -18/2 = -9 x = -1 or x = -9 I hope I didn't make any silly error here, excuse me if I did.
Oops, in the first equation it shouldn't be c^2, rather just c. sorry D:
for quadratic equation ax^2 +bx + c = 0, its two roots are found by what we call quadratic formula which is given below x1=[-b+sqrt(b^2-4ac)] / 2a x2= [-b-sqrt(b^2-4ac)] / 2a x1 and x2 are two roots of quadratic equation ax^2 +bx + c = 0 for any given quadratic equation, compare the coefficients of x^2, x^1 and x^0(constant term of given equation) which are a, b and c respectively, and put them in above formula to get answer.
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