Question

tan inverse cos x/1-sin x
write in simplest form?

Answer 1

What's wrong with your picture?

Answer 2

ans will be \[\pi/4 + x/2\]

Answer 3

do you mean
\[\frac{\tan(\cos^{-1}x)}{1-\sin x}\]?

Answer 4

hoe to get there/

Answer 5

after tan inverse i+tanx\2 /1- tan x\2 wt is the next step/

Answer 6

s to lifesaver

Answer 7

I meant... did you ask to simplify the expression I wrote down?

Answer 8

s sir

Answer 9

step for solving 1- conver cosx into cos^x/2- sin^2x/2 and 1- sinx = sin^2x/2 + Cos^2x/2 - 2sinx/2cosx/2

Answer 10

can u say step by step plz

Answer 11

Let x = cos y. Then
\[\sqrt{1-x^2}=\sqrt{1-\cos^2y}=\sqrt{\sin^2y}=\sin y\]
Hence
\[\tan(\cos^{-1}x)=\tan y=\frac{\sin y}{\cos y}=\frac{\sqrt{1-x^2}}{x}\]
and therefore
\[\frac{\tan(\cos^{-1}x)}{1-\sin x}=\frac{\sqrt{1-x^2}}{x(1-\sin x)}\]
I think this doesn't simplify further.

Answer 12

u can call me and ask this problem... my no is +91 -9706994872

Answer 13

sir i don't have a mob

Answer 14

does this ans satissfies my above question?

Answer 15

yes this is the only ans for ur question....
π/4+x/2

Answer 16

how this both links sir?

Answer 17

step for solving 1- conver cosx into cos^x/2- sin^2x/2 and 1- sinx = sin^2x/2 + Cos^2x/2 - 2sinx/2cosx/2


after this just factorize Nr and Dr and then ...it becomes tan(pi/4+x) so tan inverse cancil out tan and ans will be π/4+x/2

Answer 18

if i dont disturb u can u wright it in steps i can't read it plz

Answer 19

hey r u fed up with me/

Answer 20

ok u will send me sir i got to go for bath.