Question

Find the center, the radius, the x intercepts and y intercepts for the circle...
x^2 + y^2 -8x +6y-11=0

Answer 1

Complete the square the x and y vaiables independently
(x^2-8x+16)+(y^2+6y+9)=11+16+9
Put in standard form
(x-4)^2+(y+3)^2=36
Center (4,-3); radius=6
(cont)

Answer 2

Sorry not working at home. I din't get the line breaks that I expected--I hope you can read it.

Answer 3

it's ok

Answer 4

indeed i got that first part but I'm lost after this u.u

Answer 5

You can get the x-int by letting y=0 and solving for x:
(x-4)^2+(0+3)^2=36 or (x-4)^2=27 then square root and add 4 to get: x=4+3sqrt(3) union x=4-3sqrt(3)

Answer 6

Get y-ints by letting x=0 and solving for y: (0-4)^2+(y+3)^2=36 or (y+3)^2=20; then square root and subtract 3 to get: y=-3+2sqrt(5) union y=-3-2sqrt(5)

Answer 7

I'm on a school computer and I can't seem to get line breaks, ansd I can't use the equation editor. Sorry!

Answer 8

its completely fine! dont worry and thank you

Answer 9

You are welcome