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help with inverse? find inverse of A(t)= 75-14ln(1+t)?
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14ln(1+t) = 75 - A ln(1+t) = (75-A)/ 14 1+ t = e ^(75-A)/ 14 t = e ^(75-A)/ 14 - 1 inverse A(t)-1= [ e ^(75-t)/ 14) ]- 1
along with that I am confused on how to find t if A(t)=50?
ok use t = e ^(75-A)/ 14) - 1 = e^((75-50)/ 14) - 1 = e^(25/14) - 1 = 4.964 to 3 dec. places
ohh okay thats why i didnt get that part. it makes sense now
fine
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