The graph of f is given. Use the graph to compute the quantities asked for, if a = 31. a) lim f(x) x -> -31¯ b) lim f(x) x -> -31 c) lim f(x) x -> (-31) d) lim f(x) x -> +∞
Posting a picture of the graph, two secs. This limit stuff is owning my brain. =/
The graph seems to be the confusing part there! But a limit is essentially what y-value the graph approaches when it gets close to a certain x-value. If a value has a -, it is approached from the left. A value with a + is approached from the right. Is this review so far?
Yes, all of what you said I understand for the most part. But I just can't figure out the limits for this graph . . . and I'm not sure where I'm messing up at. >_<
So let's look at problem (a). It wants you to approach the graph from the left, and find the value of "y" at -a. You'll only look at the part of the graph in Quadrant II, the top left quadrant, because you're coming from the left. At -a (a.k.a -31), the y-value is approaching 2a, so: \[ \lim_{x \rightarrow -31^{-}}=2a\]
So the limit would have to be 62, right?
Yes!
Ahhh okay, I think I was confusing myself with both of the different graphs on 31. . . . I was looking at the closed circle line.
Ah, yes, the +/- will tell you which to look at!
Ummm, I know that a limit does not exist if the left and right limits do not match up. So limit as x approaches -31 doesn't exist. But umm what about f(-31) . . . what is it wanting me to do with that?
I thought if I was looking at x as it approaches +infinity, then my limit would be positive infinity? since the line doesn't stop . . . but that's not correct Q_Q
As far as the (-31) goes, it should be the same as -31. For the infinity question: Technically, your answer is right. However, proper notation says that a number approaching infinity doesn't have a limit, therefore the limit does not exist (d.n.e.).
Oh wow, I guess I was overlooking that rule, that makes sense then. Okay I think I got this limit graph thing now lol hopefully, thank you again for the help, very very much.
You're very welcome! I'm just now learning limits in Calc, so helping you helps me! :] Good luck!
Same to you too! =)
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