Question

simplify: radical x over x

Answer 1

\[\sqrt{x} / x\]

Answer 2

its okay...you are teh one helping :)

Answer 3

\[1/x ^{1/2}\]

Answer 4

how did u get taht????

Answer 5

Hopefully this posts right but here goes:
\[\sqrt{x}/x = x^{1/2}/x = 1/(x ^{1-1/2})\]

Answer 6

so can u write x^(1/2) a difent way...is it the same as 1/ (radical x)

Answer 7

x^1/2 is the same as 1/x^-1/2

Answer 8

ok...i got this explanation online but it cofuses me: this is wat they did
\[\sqrt{x}/ x = (\sqrt{x} * \sqrt{x}) / \sqrt{x} = x / \sqrt{x} = 1/\sqrt{x}\]

Answer 9

it's ultimately the same thing because \[1/\sqrt{x} = 1/x ^{1/2}\]

Answer 10

i see... so tehy are both equal expressions then..thats wat i was confused about

Answer 11

Just remember, anything to the ^1/2 power is a square root...and one you have it in power form you can use exponent rules to simplify things

Answer 12

ok thanks...ur explanation makes sense b.c i didnt undersand why the otehr solution was multiplying radicals

Answer 13

wait i have a question....after u wrote x^(1/2) / x...how does taht become 1/ (x^1-1/2)....i dont understand how or why u made it over one

Answer 14

to move x^1/2 to the bottom you need to make it x^-1/2...that's step one. Then you take 1/x*x^-1/2: since you're multiplying exponents with the same base you just add the exponents: 1 + (-1/2) = 1/2

Answer 15

does that make more sense?

Answer 16

yeah it does...thanks :)

Answer 17

sorry if ppl skip steps sometimes i get lost

Answer 18

\[\sqrt{x}/x = x^{1/2}x = 1/(x ^{1}*x ^{-1/2)}= 1/x ^{1/2} = 1/\sqrt{x}\]

Answer 19

Maybe that will help show all steps

Answer 20

ack..typo

Answer 21

one sec...gotta retype it all

Answer 22

\[\sqrt{x}/x = x ^{1/2}/x=1/(x ^{1}*x ^{-1/2})=1/x ^{1/2}=1/\sqrt{x}\]

Answer 23

the only trick here is to move x^1/2 down to the denominator by making it x^-1/2

Answer 24

oh i see...that makes sense...thanks for your help :)

Answer 25

np...sorry I didnt make it more clear :)