Question

2- a-3/a+3= a^2-3/a+3 Solve for A....any help would be great, begining to

Answer 1

\[2-\frac{a-3}{a+3}=\frac{a^2-3}{a+3}\] like this?

Answer 2

Yes!

Answer 3

i would multiply both sides by
\[a+3\] to get
\[ 2(a+3)-(a-3)=a^2-3\]
\[

Answer 4

then don't forget that a = -3 cannot be a solution. solve the quadratic

Answer 5

\[2a+6-a+3=a^2-3\]
\[a+9=a^2-3\]
\[a^2-a-12=0\]
\[(a-4)(a+3)=0\]
\[a=4\]
\[a=-3\] but don't forget you had
\[x+3\] in your original denominator, so -3 is not a solution and you just have
\[x=4\]