A manufacturer of a product has fixed costs totaling $8295. He finds he can never sell any of the product unless the price is below $97, and for each decrease of $5 in the price, he is able to sell 100 more units. Find the cost function, demand function, revenue function, and profit function
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OpenStudy (anonymous):
Each unit costs an additional $47 to produce
OpenStudy (anonymous):
C(x) = 8925 + 47 x , thats all i got, cant do the demand equation
OpenStudy (amistre64):
what do you mean by "each unit costs and additional" ? is that just 45 per unit?
OpenStudy (amistre64):
47 if i read it right lol
OpenStudy (anonymous):
, yes, per item it costs 47 to produce
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OpenStudy (anonymous):
, i need help with the demand equation
OpenStudy (anonymous):
fixed costs means like overhead, building and stuff
OpenStudy (anonymous):
rent
OpenStudy (amistre64):
fixed costs = 8295.
price < 97
-5 in the price, sell +100
Find the cost function, demand function, revenue function, and profit function
Cost(x) = 47x + 8295
Revenue(x) = x*Quantity(x)
Quantity(x) = has a slope of 100/-5 = -20
= -20x +20(Px) +Py, if its linear
OpenStudy (amistre64):
Quantity would mean Demand
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OpenStudy (amistre64):
how much can they sell at $97 tho
OpenStudy (anonymous):
where is your demand function
OpenStudy (amistre64):
still working on it, but itd be nice to know how much can be sold at a given price
OpenStudy (amistre64):
97,0 maybe
OpenStudy (anonymous):
i guess we start with 97 as the price
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OpenStudy (anonymous):
(97,0) and (92, 100)
OpenStudy (amistre64):
Demand(x) = has a slope of 100/-5 = -20
= -20x +20(97)
= -20x +194
OpenStudy (anonymous):
let quantity demanded be a function of price
OpenStudy (amistre64):
i dropped a zero :)
Demand(x) = -20x+1940
OpenStudy (anonymous):
, wait, where did you get x?
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OpenStudy (amistre64):
x is just what im using for price
OpenStudy (anonymous):
i have D = -20 p + 97
OpenStudy (anonymous):
x should stand for units sold
OpenStudy (amistre64):
your wrong on that
OpenStudy (anonymous):
we used x earlier for units sold
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OpenStudy (amistre64):
change x to p then :)
OpenStudy (amistre64):
D(p) = -20p +1940
OpenStudy (anonymous):
actually , the units sold are the quantity demanded
OpenStudy (anonymous):
so we have x = -20 p + 97
OpenStudy (amistre64):
not 97
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OpenStudy (amistre64):
at p=97 you sell 0
OpenStudy (anonymous):
one sec
OpenStudy (amistre64):
0 = -20(97) + C
OpenStudy (amistre64):
C = 1940
OpenStudy (anonymous):
hmmm, i thought (97,0) is the y intercept
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OpenStudy (amistre64):
x intercept :)
OpenStudy (amistre64):
or rather, price intercept
OpenStudy (amistre64):
graphic wise it can be whatever axis you want to put it on
OpenStudy (anonymous):
we have (97,0) and (92,100)
OpenStudy (anonymous):
we are drawing the line through those two points
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OpenStudy (amistre64):
slope was given as 100/-5 to begin with = -20
OpenStudy (anonymous):
(price, units sold/quantity demanded)
OpenStudy (amistre64):
the price intercept (97,0)
OpenStudy (anonymous):
so it should be x = -20 p + 97
OpenStudy (anonymous):
oh no
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OpenStudy (amistre64):
D(p)= -20p + C , at a price intercept would to the independant variable
OpenStudy (anonymous):
youre right
OpenStudy (amistre64):
thats why i used "x" to show price
OpenStudy (anonymous):
ok so x = -20 p + 1940
OpenStudy (amistre64):
but p is fine, just as long as we know where its going :)
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