Question

the perimeter of a rectangle is 82m the length is 2m more than twice the width . what would the demenisions be then?

Answer 1

let the width be x and length be 2x+2
perimeter=2(l+w)
82=2(2x+2+x)
3x+2=82/2
solve for x

Answer 2

The width can be represented as W and the length can be represented as L = 2W + 2

The perimeter of the rectangle is 82m, and the formula for perimeter is P = 2L + 2W, So we can plug the numbers in and do the following ...

P = 2L + 2W
82 = 2(2W + 2) + 2W Multiply 2 to what is inside the parenthesis
82 = 4W + 4 + 2W Subtract 4 on both sides and combine like terms (4W + 2W = 6W)
78 = 4W Divide by 6 on both sides
W = 13

So we come to the conclusion that the length L is equal to 28 meters and the width W is equal to 13 meters. We can check out answer by using the perimeter formula.

2L + 2W
2(28) + 2(13) = 82

Our answer is complete.