Question

Given the quadratic function f(x) = 16x2 – 64x + 64, find a value of x such that f(x) = 16

Answer 1

if f(x) = 16, then:

16x² - 64x + 64 = 16

simplify by dividing through by 16:

x² - 4x + 4 = 1

subtract 1 from both sides:

x² - 4x + 3 = 0

factor:

(x - 3)(x - 1) = 0

solve:

x = 3 or x = 1

There are two values of x such that f(x) = 16:

f(3) = 16 and f(1) = 16