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Solve the integral: 1 / (e^x + 1) Explain thoroughly the algebraic step that is necessary.
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hmm....
\[\int\frac{1}{e^x+1}dx\] if we had an e^x up top we could ln it
do we multiply by a conjugate?
add zero to the top?
add zero is what id try
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\[\int\frac{1+(e^x-e^x)}{e^x+1}dx\] \[\int\frac{1+e^x-e^x}{e^x+1}dx\] \[\int\frac{1+e^x}{e^x+1}-\frac{e^x}{e^x+1}dx\] \[\int\ 1-\frac{e^x}{e^x+1}dx\] \[x - ln(e^x+1)+C\]
Nicely done, thanks.
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