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Mathematics 22 Online
OpenStudy (anonymous):

matrices help!

OpenStudy (anonymous):

OpenStudy (anonymous):

^ see attached

OpenStudy (anonymous):

My thoughts were that if I can prove that R * R^t (its transpose) were equal to 1 then R^t = R^-1 (inverse)

OpenStudy (anonymous):

R^T =[ 2/7 6/7 -3/7 ] [6/7 3/7 2/7] [3/7 2/7 6/7]

OpenStudy (anonymous):

did you try to get the inverse?

OpenStudy (anonymous):

wouldnt the first 6/7 on second row be neg?

OpenStudy (anonymous):

I haven't tried to get the inverse yet.

OpenStudy (anonymous):

yes negative im sorry my pc keeps hanging up on me lol

OpenStudy (anonymous):

try to get the inverse

OpenStudy (anonymous):

to get the inverse i have to find the determinant of the matrix and the transpose then i get a adjoint matrix then I divide the adjoint matrix by the determinant?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

k, brb have to try to do this on paper.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

the answer would be the same as the R transpose

OpenStudy (anonymous):

ffor the determinate R i got this

OpenStudy (anonymous):

R^1= R adj / /R/

OpenStudy (anonymous):

\[2/7(3/7*6/7-2/7*2/7)-6/7(-6/7*6/7-2/7*3/7)+-3/7(-6/7*2/7-3/7*3/7)\]

OpenStudy (anonymous):

detR=/R/ = 1

OpenStudy (anonymous):

is /R/ the adjoint of matrix? Sorry this stuff is pretty confusing to me

OpenStudy (anonymous):

/R/ is the determinant of matrix R it is also det R=/A/

OpenStudy (anonymous):

R adj= adjoint of R

OpenStudy (anonymous):

okay. I tried to get the det R for the matrix above following http://analyzemath.com/Tutorial-System-Equations/determinants.html

OpenStudy (anonymous):

which resulted in 1

OpenStudy (anonymous):

like you said

OpenStudy (anonymous):

ok thats good for the det R, now you can get the adjoint, try doing it

OpenStudy (anonymous):

okay, brb, back to the note book haha

OpenStudy (anonymous):

ok have fun lol

OpenStudy (anonymous):

could you give me a little help, the books example on adjoint of the matrix is not very clear.

OpenStudy (anonymous):

ok ill give you a good example hold on

OpenStudy (anonymous):

okay, thanks again for the help

OpenStudy (anonymous):

I think i may have gotten it, It came out the same as the tranpose matrix

OpenStudy (anonymous):

if A=[ 1 2 3 ] [ 0 4 5 ] [ 1 0 6 ] you need to find the cofactor of each A11=[ 4 5 ] = 24 A12= -[ 0 5 ] [ 0 6] [ 1 6 ] =5 A13 =[ 0 4 ] [ 1 0 ] = -4 A21=-[ 2 3 ] [ 0 6 ]= -12 etc.... then you will have cofactor of A= [ 24 5 -4] [ -12 3 2] [-2 -5 4] then you can have adj A =[ 24 -12 -2 ] [ 5 3 -5] [ -4 2 4]

OpenStudy (anonymous):

note here i use the co factor instead of the transpose

OpenStudy (anonymous):

perfect I found a cofactor example too that help me along, thanks :)

OpenStudy (anonymous):

yes the adj R is the same as transpose,,but they are not all the time equal....inthis case they are only equal

OpenStudy (anonymous):

ok hope that help you out

OpenStudy (anonymous):

perfect ! so i proved the second part! awesome thanks so much for your help

OpenStudy (anonymous):

ok now have fun

OpenStudy (anonymous):

yes, I guess my only other question is what did it mean by a proper rotation matrix?

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