Question

How do you solve the algebraic equation (16/81)^-1/3

Answer 1

(16/81)^-1/3
= 1/(16/81)^1/3
= \[1/\sqrt[3]{16/81}^1\]

Need any further explanation?

Answer 2

you can easily solve by logirthm

Answer 3

The answer isn't the problem I know the answer just not how to get the answer

Answer 4

in fact it is not an equation, it is a number. the number is
\[(\frac{81}{16})^{\frac{1}{3}}\]

Answer 5

rather it means
\[\frac{\sqrt[3]{81}}{\sqrt[3]{16}}\]

Answer 6

since
\[16=2^4\] and
\[81=3^4\] you can rewrite this as
\[\frac{3\sqrt{3}}{2\sqrt{2}}\]

Answer 7

dang i am making mistake after mistake. i meant it is
\[\frac{3\sqrt[3]{3}}{2\sqrt[3]{2}}\]

Answer 8

Some how it is supposed to be 3.375

Answer 9

then it is a calculator exercise

Answer 10

at satellite73 the problem actually is how to find 2^(1/3)

Answer 11

take the cubed root of
\[\frac{81}{16}\] and see what you get

Answer 12

Not supposed to be

Answer 13

and the method is similar as to find out square root of 3

Answer 14

newton's method? is that what you are using?

Answer 15

which newton's method are you thinking

Answer 16

the method I'm talking it's the method that I learnt in primary class.

Answer 17

and I don't know who gave this