Ask
your own question, for FREE!
Mathematics
6 Online
OpenStudy (anonymous):
inverse of y=2x^4, y=4-x^2
Join the QuestionCove community and study together with friends!
Sign Up
myininaya (myininaya):
not 1 to 1
=>
no inverse
OpenStudy (anonymous):
so what are the restricted domains
myininaya (myininaya):
yes perhaps if you were given some restricted domain we could say we have an inverse
OpenStudy (anonymous):
so what is the restricted domain of the original problem
myininaya (myininaya):
i don't what does it say?
Join the QuestionCove community and study together with friends!
Sign Up
myininaya (myininaya):
and also if you did have a restriction on the domain such that the function is 1 to 1
then the inverse you have above is incorrect
OpenStudy (anonymous):
there is \[2x^{4} and 4-2x^{2} \]
myininaya (myininaya):
2x^4 and 4-2x^2 are not inverses for each other over any restricted domain
myininaya (myininaya):
y=2x^4 is not 1 to 1
does not have inverse
myininaya (myininaya):
she/he never provided us with domain restriction
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
how do your restrict the domain of \[27x^{3}\]
myininaya (myininaya):
does it ask you to choose a restriction such that function is 1 to 1?
myininaya (myininaya):
27x^3 is 1 to 1
myininaya (myininaya):
\[y=27x^3 => \frac{y}{27}=x^3 => \sqrt[3]{\frac{y}{27}}=x=> f^{-1}(x)=\sqrt[3]{\frac{x}{27}}\]
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol:
bro how
4 days ago
1 Reply
2 Medals