Can anyone help me: \[\int {\frac{{dx}} {{\sqrt {1 + {e^{2x}}} }}} \]
I have a vague feeling it should do integration by parts...Or make some change to the form...
Please take your time.
use wolfram.. :D
I know the answer. But it is a question on a exam. So...I have to know how...
wolfram is pretty good at explaining in my eyes.
Sorry, I confused myself a little: I think you have to look at the expression under the sqare root as 1+(e^x)(e^x), which would mean you could use a trig substitution... I am just learning trig substitution though, but it's the only way I see to do it. Let x=1tan(theta) and see what happens... Not sure it will work.
I guess a u substitution would get you to the same place... sorry i wasn't much help :/
I got it . You are right, i done it with trig substitution. Thanks a lot.
Sweet, I'm glad you got it because I got stuck, haha. What was the answer?
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