Factor completely:
35x^3-225x^2+250x
Step by step please

Question

saifoo.khan · Answer

go for commons.

saifoo.khan · Answer

5x(7x^2 -45x + 50)

Now factor the brackets.

saifoo.khan · Answer

$$5x(x-5) (7 x-10) $$

anonymous · Answer

@saifoo.khan how did you factor inside the bracket?

chaise · Answer

$$35x^3-225x^2+250x$$
$$=5x(7x^2-45x+50)$$
$$=5x(x-5)(7x-10)$$

saifoo.khan · Answer

http://www.youtube.com/watch?v=_BGAOjZzeCI

saifoo.khan · Answer

http://www.youtube.com/watch?v=AMEau9OE6Bs

anonymous · Answer

Basically, what can you multiply to get the last number, and with these same numbers, add to get the middle number?

anonymous · Answer

Also if there's a coefficient in front of the x^2 then it's mostly guess and check.  That's my way.

anonymous · Answer

@brandon376 if it's like you said how would -5 + -10 = -45? o_o

chaise · Answer

There is a method to solving them - factors of 7 and factor of 50 which cross multiply and then add to give -45. Difficult process made easy by the calculator.

anonymous · Answer

There's a 7 though

anonymous · Answer

@chaise can you please explain more

anonymous · Answer

x(35x^2-225x+250)

=5x(7x^2-45x+50)
=5x(7x^2-35x-10x+50)
=5x(x-5)(7x-10)