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Mathematics 21 Online
OpenStudy (anonymous):

reduce this fraction with exponents..

OpenStudy (anonymous):

OpenStudy (anonymous):

Take an x out of the top and the bottom.

OpenStudy (chaise):

\[\frac{x^3+x^2}{2x^2+x}\] \[=\frac{x(x^2+x)}{x(2x+1)}\] Your x's outside the brackets cancel. \[=\frac{(x^2+x)}{(2x+1)}\] You can probably factor out another x into the top half of the equation. I believe this is as far as you can go. \[=\frac{x(x+1)}{(2x+1)}\]

OpenStudy (anonymous):

\[\frac{x(x^{2}+x)}{x(2x+1)}\]

OpenStudy (anonymous):

thx .. which button in equation does the ------- that separates the fraction

OpenStudy (chaise):

frac{top}{bottom} You have to type it in manually I'm afraid.

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