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reduce this fraction with exponents..
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Take an x out of the top and the bottom.
\[\frac{x^3+x^2}{2x^2+x}\] \[=\frac{x(x^2+x)}{x(2x+1)}\] Your x's outside the brackets cancel. \[=\frac{(x^2+x)}{(2x+1)}\] You can probably factor out another x into the top half of the equation. I believe this is as far as you can go. \[=\frac{x(x+1)}{(2x+1)}\]
\[\frac{x(x^{2}+x)}{x(2x+1)}\]
thx .. which button in equation does the ------- that separates the fraction
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frac{top}{bottom} You have to type it in manually I'm afraid.
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