What is the solution to the following system using Cramer’s Rule?

2x + 7y = 2
3x + 8y = –2

Question

What is the solution to the following system using Cramer’s Rule?

2x + 7y = 2
3x + 8y = –2

anonymous · Answer

nevermind were good

anonymous · Answer

okay a1=2 and b1=7 c1=2....................a2=3 and b2=8 and c2=-2..........$$ D=\left[\begin{matrix}a1 & b1 \ a2 & b2\end{matrix}\right] =a1b2-a2b1=2*8-3*7=-5$$

anonymous · Answer

I'm so lost..

anonymous · Answer

$$Dx=\left[\begin{matrix}c1 & b1 \ c2 & b2\end{matrix}\right] =c1b2-c2b1=2*8--2*7=30$$

anonymous · Answer

the letters a1 b1 c1 are the coefficients the numbers that are in front of the x y and z, cramers rule involves matrices and determinants

anonymous · Answer

$$Dy=\left[\begin{matrix}a1 & c1 \ a2 & c2\end{matrix}\right] =a1c2-a2c1=2*-2-3*2=-10$$

anonymous · Answer

the solution x=Dx/D =30/-5=-6 and y=Dy/D=-10/-5=2

amistre64 · Answer

2x + 7y = 2
3x + 8y = –2

y = -2(2)-3(2) / 8(2)-3(7)

x =  -2(7)-8(2|dw:1315585996180:dw|) / 3(7) - 8(2)

amistre64 · Answer

well that inserted in the wrong place altogether :)