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In 3.45 mg of boron there are how many of the following? grams of boron? moles of boron? boron atoms?
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\[3.45mg \times \frac{1g}{1000mg}=0.00345g\]This is basic dimensional anaysis. You will have better luck on the chemistry site for the other two questions, I think.
moles of boron = .00345/relative atomic mass of boron in grams for the third part you need to use the number of atoms in 1 mole of born which is Avogadros Number whose value i cant recall
Moles = Mass(g)/MW Moles = 0.003.45/10.811 Moles = 0.32 There are 0.00032 moles of Boron in 3.45mg or 0.00345g.
6.02x10 to 23rd power
thanks all of you so much!!!
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