Question

The position of a particle moving along the x axis varies in time according to the expression x = 4t 2, where x is in meters and t is in seconds. Evaluate its position at the following times.

(a)t=2.10s
______m

(b)t=2.10s +Δt
xf=________m

(c)Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 2.10 s.
_______m/s

Answer 1

for a i got 17.64..what did you guys get?

for b and c i have no idea lol

Answer 2

for a) you are correct

not sure about part b)

looks like for part c) they are looking for velocity at time t =2.1
take the derivative
--> d/dt 4t^2 = 2*4t = 8t
plug in 2.1

Answer 3

it looks like part b i need to put some special characters in =/

Answer 4

oh wait part b is just plugging in (t+delta t) for t

--> x = 4(t+delta t)^2

Answer 5

8(2.1)=16.8?

Answer 6

yes

Answer 7

ok so a is what i got....b is what u wrote? and c is 16.8?

Answer 8

yes, just replace t with 2.1 with what i wrote for part b

Answer 9

wait lol..so it will be 4(2.1+delta2.1)^2??

Answer 10

haha no its still the delta symbol t

Answer 11

ok lol

Answer 12

YYEYEEAAAAAA!!!!! it was right!!!!

Answer 13

you are amazing! again..may have more!