Question

Anyone have any idea how to factor these?

Answer 1

\[x^6-27y^6\]

Answer 2

\[8c^6+19c^3-27\]

Answer 3

Sorry the first one is
\[x^6-27y^3\]

Answer 4

8c^6+19c^3−27
Let c^3 = x

8x^2+19x−27
Factorise like normal a normal quadratic.
(x-1)(8x+27)
Replace your x with c^3.
(c^3-1)(8c^3+27)

Answer 5

First one is difference of cubes
a^3 - b^3 = (a-b)(a^2 +ab +b^2)