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Mathematics 16 Online
OpenStudy (anonymous):

Question below in picture...because its a graph =(

OpenStudy (anonymous):

OpenStudy (anonymous):

anyone?!

myininaya (myininaya):

average velocity is change y over change of t

myininaya (myininaya):

just count over 3 times on the x-axis and count up by 3's until you get to the curve to figure out what y is

myininaya (myininaya):

it is too blinding to me

OpenStudy (anonymous):

webassign lol

myininaya (myininaya):

.25(3)=.75 i counted 8(3) going up the curve

myininaya (myininaya):

but i'm not sure if thats right since i went crosseyed doing so

OpenStudy (anonymous):

you really have to count carefully here. very hard to see

myininaya (myininaya):

so that's one ordered pair we will use (.75,24)

myininaya (myininaya):

now it says to use (2,?) also to find average velocity

myininaya (myininaya):

(2,3(2))=(2,6)

OpenStudy (anonymous):

for the first part, draw a secant line (touches the graph in two spots i think) between the point on the yellow curve where time is .75 and the point where time is 2.00. Measuer the slope of that line

myininaya (myininaya):

so use your slope formula to figure out the slope of the secant line passing through (.75,24) and (2,6)

OpenStudy (anonymous):

fo rthe second part measure the slope of the green line

OpenStudy (anonymous):

for the third part velocity is zero at minimums and maximums, in other words where the orange graph starts increasing.

OpenStudy (anonymous):

i hate this question =(

myininaya (myininaya):

i know this doesn't help you but i hate your question that is really bad for one's eyes

myininaya (myininaya):

but i did help you with the first one

OpenStudy (anonymous):

lol i'm sorry..i just need help lol

myininaya (myininaya):

do you know how to find the slope of that line running though (.75,24) and (2,6)

myininaya (myininaya):

\[\frac{24-6}{.75-2}\]

OpenStudy (anonymous):

slope formula....which is i think y2-y1/x2-x1?

OpenStudy (anonymous):

or opposite lol

myininaya (myininaya):

no thats fine

OpenStudy (anonymous):

-15.2?

myininaya (myininaya):

hmmm i got something different

myininaya (myininaya):

-14.4 is what i got

OpenStudy (anonymous):

now i got ur answer lol

myininaya (myininaya):

\[\frac{24-6}{\frac{3}{4}-2}=\frac{18}{\frac{3}{4}-\frac{8}{4}}=\frac{18}{\frac{-5}{4}}=-18 \cdot \frac{4}{5}=\frac{-72}{5}\]

myininaya (myininaya):

now for second one do you see that tangent line at t=1?

OpenStudy (anonymous):

yea i got your answer now

OpenStudy (anonymous):

it tells me that it is

myininaya (myininaya):

use the x-intercept and the y-intercept of that line to find the slope of that line by using that same formula

myininaya (myininaya):

or i mean t-intercept (not x)

OpenStudy (anonymous):

so....it would be.....(0,13)?

myininaya (myininaya):

(0,13(3)) is y- intercept that is (0,39)

OpenStudy (anonymous):

oh sorry...didnt see the rest of your comment

myininaya (myininaya):

now we need to find the t-intercept

myininaya (myininaya):

(7(.25),0) is t-intercept that is (1.75,0)

myininaya (myininaya):

now do \[\frac{39-0}{0-1.75}=\frac{-39}{1.75}\]

myininaya (myininaya):

=-156/7

OpenStudy (anonymous):

-22.29?

myininaya (myininaya):

are you allow to approximate? if so yes

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

yay! im doing well =)

myininaya (myininaya):

the last one is t=8(.25) since we can draw a horizontal tangent there

myininaya (myininaya):

8(.25)=2 right?

OpenStudy (anonymous):

yes

myininaya (myininaya):

now i need to take a break my computer is blinding me lol

OpenStudy (anonymous):

lol sorry

OpenStudy (anonymous):

but u are amazing thanks for the help =)

myininaya (myininaya):

its not your fault

OpenStudy (anonymous):

=)

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