Question

the value of (sinq-cosq)^2+(sinq+cosq)^2 is equivalent to

Answer 1

sin²q+cos²q+sin²q+2sinqcosq +cos²q
2sin²q+2sinqcosq+2cos²q
2(sin²q+sinqcosq+cos²q)

Answer 2

2

Answer 3

pls explain please

Answer 4

For my answer, I simply factored out the equation you posted. But xen claims it's a trig identity, and that could be so as well.. That's all I can do.

Answer 5

(sinq-cosq)^2=\[\sin^{q}+\cos^{2}q-2sinqcosq\],also(sinq+cosq)^2=\[ \sin^{2}q+\cos^{2}q+2sinqcosq\] using formulas of (a+b)^2 and (a-b)^2 and the standard definition \[\sin^{2}q+\cos^{2}q=1\].... you get
1-2sinqcosq and 1+2sinqcosq
now add both
1+1=2