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If a and b are positive integers and their product is 3 times their sum, what is the value of (1/a) + (1/b)?
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\[ab = 3(a+b)\]
I know how to set up the equation... I need help with the algebra LOL.
ab=3(a+b) ==> a=3(a+b)/b ===> (1/a) + (1/b) = 1/[3(a+b)/b+1/b = b/3(a+b) + 1/b = [b^2+3a+3v]/[3ab+3b^2]
Sorry but I can't read it... do you mind drawing it out? ><
ok
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\[ab=3(a+b) ==> a=3(a+b)/b ===>\] \[(1/a) + (1/b) = 1/[3(a+b)/b+1/b\]\[ = b/3(a+b) + 1/b = [b^2+3a+3v]/[3ab+3b^2] \]
|dw:1315643561253:dw|
you may expand the bracjets also
It's SAT math, so the answer has numerical digits :'( It's the free response.
\[\frac{1}{a}+\frac{1}{b}=\frac{-3}{3b-ab}-\frac{3}{3a-ab}\]
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sin ab=3(a+b) divide ab on both side so (1/a+1/b)=1/3
Thank you.
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