Question

a die is biased so that the probability of rolling a 1,2,3,4,5,6 is 0.25,0.2,0.2,0.1,0.15 and 0.2 respectively.

If the die is rolled twice, the probability that the sum of the two numbers rolled is greater than 9 is?

Answer 1

sorry the probabilities are 0.25, 0.2, 0.1, 0.1,0.15 and 0.2

Answer 2

(4,6)+2(5,5)+(6,5)+(5,6)+(6,4)
0.02+0.045+0.03+0.03+0.02

=0.145

Answer 3

the answer is 0.1625

Answer 4

i get 0.225 lol I'm so lost

Answer 5

ill do it agaon since you posted new probabilities and i forgot 1 thinmg in my answer

Answer 6

6,6

Answer 7

.225

Answer 8

yeah i got that and its wrong lol

Answer 9

2(4,6)+2(5,5)+2(6,5)+2(6,6)

0.04+0.045+0.006+0.04

Answer 10

oops its 0.04+0.045+0.06+0.04

Answer 11

still wrong :(

Answer 12

.1625

Answer 13

yeah dam lol

what i did was this

2(0.1 x0.2) + 2(0.15 x 0.2) +2(0.15 x0.15)+ 2(0.2 x0.2)

Answer 14

it seems right but i guess not

Answer 15

soory i include 9 as well
(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)
2(.1*.2)+2(.15*.2)+.15^2+.2^2=.1625

Answer 16

oh thats weird cause it says greater than nine. thanks a lot for the:)