Express answer in exact form.

A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.

(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4 s2 √3.)
Don't multiply out. I need it in something like this: (9/2)*pi - (9/2)*sqrt3.
I need help! This is assignment is already late, but I can't figure the problems out!

Question

Express answer in exact form.

A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.

(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4 s2 √3.)
Don't multiply out. I need it in something like this: (9/2)*pi - (9/2)*sqrt3.
I need help! This is assignment is already late, but I can't figure the problems out!

anonymous · Answer

1/6 of circle = 9pi/6  = 3pi/2  minus

9 sqrt 3/4

anonymous · Answer

Oh my gosh thank YOU sooooooooooooooooo much!

anonymous · Answer

ur welcome.