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If xy = 5, evaluate log base 5 (x^2 *y^2). Help! This is driving me crazy!
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=2
I think it would be 2. \[\log_{5} (x^{2} \times y^{2}) \] if xy = 5, then I think this could be substituted/simplified as \[\log_{5}(5^{2}) = 2\log_{5}(5) = 2 \times 1 = 2\]
here xy=5 log base5(x^2y^2) =log base5(xy)2 =2logbase5(5) since log base5(5)=1 ans is 2
Is it OK
log base5(xy)^2 =log base5(5)^2 =2log base5(5) =2x1=2 ans
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any question?
Thanks everyone! No questions. I knew it was an easy one but could not get it.
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