Question

2 logbase8(x) = logbase8(2) + logbase8(3x + 8). solve this analytically?

Answer 1

log8 x^2 = log8 (6x+16)
x^2 = 6x + 16
x^2 - 6x - 16 = 0
(x+2)(x-8) = 0
x = -2 , 8

Answer 2

\[\log_{8} x^{2} = \log_{8} (2 \times(3x +8)) \]\[x ^{2} = 6x + 16\]

on solving the quadratic eqn.
=> x = 8,-2

Answer 3

i put in -2,8 and its wrong? are one of those not right?

Answer 4

actually -2 isn't right as per the given original equation since log is not defined for negative numbers.
so the answer is only 8 if u ask me

Answer 5

yea thats what i thought and yea just 8 is right