Question

Ok i am having problems here

\[\frac{\frac{1}{x+2}-5}{\frac{4}{x}-x}\]

i need to simplify

Answer 1

get common denominator in the numerator and denominator individually, then invert the denominator and multiply and reduce.

Answer 2

multiply the top by 4/x - x

Answer 3

\[\frac{4x-x^2}{x}\]

Answer 4

is that the bottom?

Answer 5

yep

Answer 6

This is what i'm thinking is simplest
\[\frac{\frac{12-4x}{x+2}}{4-x}\]

Answer 7

\[\frac{\frac{1}{x+2}-5}{\frac{4}{x}-x}=N\]
\[\frac{1}{x+2}-5=N(\frac{4}{x}-x)\]
\[\frac{1(x+2)}{x+2}-5(x+2)=N(\frac{4}{x}-x)(x+2)\]
\[x(1-5x-10)=N(x)(\frac{4}{x}-x)(x+2)\]
\[5x^2+9x=N(x^2-4)(x+2)\]
\[5x^2+9x=N(x-2)(x+2)(x+2)\]
\[5x^2+9x=N(x-2)(x+2)^2\]
where are we going with this?

Answer 8

i'm not sure the dirctions say "Simplify the expression" so i was attempting to simplify

Answer 9

So why did you set it = to N?