Question

a projectile is fired with an initial speed of 500m/s and angle of elevation 30 degrees. find the range, max height and speed at impact

Answer 1

range = \[12500\sqrt{3}\]

max height = 18750
speed at impact= 500m/s

Answer 2

range = \[2 \times Vox \times t\]
with t is the time of projectile on max height position

Answer 3

the time of projectile on max height position, when Vty (on y axis) is zero
So using equation Vt=Voy - at // a = gravity
Vt = (Initial speed) x (sin 30) - 10 t
0 = 500 sin30 -10t
\[0=250\sqrt{3}-10t\]\[t = 25\sqrt{3}\]

Answer 4

thanks this helped a lot!