Question

Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11

Answer 1

Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11

Answer 2

Find the slope of 10x-6y=-11
Take the opposite reciprocal of the slope, that will make the new equation perpendicular to it.

Answer 3

y=-3/5 x+b ===> -8=15+b==>b=-23===<y=-3/5 x -23

Answer 4

http://takeexam.next.ecollege.com/ec/courses/41110/CRS-MAT0099-4323816/ContentItem_112154461/image5354c81d92c.gif

Answer 5

http://takeexam.next.ecollege.com/ec/courses/41110/CRS-MAT0099-4323816/ContentItem_112154461/image5354c81d92c.gif

Answer 6

As precal stated find the slope of the line represented by 10x-6y=-11 rearranging to the slope intercept form: -6y=-10x-11 dividing by -6 to get: y=(10/6)x+11/6, m the slope is 10/6 or5/3 Take the negative reciprocal of the slope to get the slope of a line that is perpendicular which is -(3/5).

Now use the point slope formula to get the equation of the perpendicular line:
-3/5 = (-8-y)/(-5-x)
15+3x=-40-5y
-5y=3x-55
y=(3/-5)x-11 or y=-(3/5)x-11