Question

elimination method
0.3x-0.2y=4
0.5x+0.5y=-45/17

Answer 1

ick who gave this question with a 17 in the denominator?

Answer 2

must be tired. start with
\[3x-2y=40\]
\[x+y=-\frac{90}{17}\]

Answer 3

(1)
\[\frac{3}{10}x-\frac{2}{10}y=4\]
(2)
\[\frac{5}{10}x+\frac{5}{10}y=\frac{-45}{17}\]

multiply (1) by 10

multiply (2) by 10(17)

\[3x-2y=40\]


\[5(17)x+5(17)y=-45(10)\]

Answer 4

(1)
\[3x-2y=40\]
(2)
\[5(17)x+5(17)y=-45(10) \]

divide equation (2) by 5

Answer 5

(1)
\[3x-2y=40\]
(2)
\[17x+17y=-45(2)\]

so we have equation (2) is
\[17x+17y=-90\]

Answer 6

multiply second equation by 2 get
\[3x-2y=40\]
\[2x+2y=-\frac{180}{17}\] add and get
\[5x=40-\frac{180}{17}=\frac{500}{17}\] so
\[x=\frac{100}{17}\]

Answer 7

now are two equations look pretty right?

Answer 8

ok but satellite was much quicker so use his process

Answer 9

(blush)

Answer 10

or you can use the decimal w/c is the orig eq
0.3x-0.2y=4 mult by 0.5 0.15x-0.10y= 2
0.5x+0.5y=-45/17 mult by 0.2 +(0.10x+0.10y=-9/17) add
--------------------
0.25x +0 = 25/17
x=25/(17)(.25)
x=100/17 ans now sub this to 0.5x+0.5y=-45/17
0.5(100/17)+0.5y=-45/17
y=-11.176 ans

Answer 11

good luck stacy