Question

w4-144

Answer 1

w^2 + 12) (w^2 - 12)

Answer 2

what to do??factor?

Answer 3

or u want w

Answer 4

factor

Answer 5

Yes I believe thats what they want. Do you want the whole solution to it Nemokimo?

Answer 6

yes

Answer 7

kat is right

Answer 8

kat is always right lol

Answer 9

Okay first you have to split this into 2 equation equation terms..
So we know we have break w^4 into 2 w^2 since they will still equal w^4
Then look into the sign of the eqaution given..which is w^4 - 144
Since it is MINUS we know that we have to have a negative AND positive symbol for each equation..
So it would be
(w^2 + ___) (w^2 - ___)

Now the square of 12 is equal to 144..So we know that 12 would substiute it in the blanks..
So
(w^2 + 12) (w^2 - 12)

Adn there is your answer

Answer 10

Hehe thanks =D

Answer 11

good work katrina
\[(w^2)^2-(12)^2\]
\[(w^2+12)(w^2-12)\]

Answer 12

w^4 can also be written as (w^2)^2
and also 144 can be written as (12^2)
according to the property ( a^2-b^2 ) = (a+b)(a-b)

Answer 13

hence the answer is ::::::::::::
\[(w^2+12)(w^2-12)\]