Question

Three boys and three girls are to sit together in a row.

Find the probability that :

(a) the boys and girls alternate.
(b) the boys and girls sit together.
(c) two specific girls sit next to one another

Answer 1

ok

Answer 2

ok? lol

Answer 3

can anyone help me out?

Answer 4

good

Answer 5

good what?

Answer 6

every thing is good

Answer 7

if someone explains this question everything will be good :)

Answer 8

hahaha

Answer 9

bye

Answer 10

bye nilankshi

Answer 11

bye

Answer 12

joe helllp me lol

Answer 13

is it 2x (3! 3!/6!)

Answer 14

are we able to tell between people?

like, are these people b1, b2, b3, g1, g2, g3?
or
b, b, b, g, g, g, where we cant tell between them.

Answer 15

you can't tell

Answer 16

i dont like these problems because its never too clear.

Answer 17

lol i hate probability in general

Answer 18

my answer is right but i don't know if my method is right

Answer 19

Well, there are 2 ways we can have boys and girls alternate,

b g b g b g
or
g b g b g b

so only 2.

There are\[\frac{6!}{3!3!}=\frac{6\cdot 5\cdot 4}{1\cdot 2 \cdot 3}=20\]total combinations, so the probability is:
\[\frac{2}{20}=\frac{1}{10}\]
Which i believe is what you got for the first answer.

Answer 20

There are only 2 ways that boys can sit together and girls can sit together, namely:

b b b g g g
or
g g g b b b

so the probability will be the same again, 1/10

Answer 21

what is the formula again?

Answer 22

For the total number of combinations?

Answer 23

because my working was the other way around to yours

Answer 24

I dont really know formulas =/ I just know that since there are 6 people, the number of ways their order can be changed is 6!

This is because when i pick someone to be the first person, I have 6 people to choose from.
When I pick the second person there will be 5 to choose from.
Then 4, then 3, and so on, so the total number of combinations is:

6*5*4*3*2*1=6!

But because i cant tell the difference between the boys if i switch them around, or the girls, I over counted. I have to divide by the number of ways I can switch the boys only, and the number of ways i can switch the girls only. So i take that 6!, and divide by 3! for the boys, and again by 3! for the girls.

Answer 25

isee thanks for the explanation :)

Answer 26

so c ) will be 6!/4!2!

Answer 27

yes . it's 6P2 = 6!/4! 2!