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Mathematics
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x^2 + 5x +6 over x^2 + x -6 times x^2-9 over x^2-x-6
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\[[(x+3)(x+2)]/[(x+3)(x-2)] * [(x-3)(x+3)]/[(x-3)(x+2)]\]
now you will note there are common factors: (x+3) in the first part, and (x-3) in the second part which cancel.
to give you: \[[(x+2)]/[(x-2)] * [(x+3)]/[(x+2)]\]
now if we multiply these we get: \[[(x+2)(x+3)/(x+2)(x-2)]\]
note above the x+2 in the numerator and denominator cancel to give: \[[(x+3)/(x-2)]\]
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That's your answer daniMarie!
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