Newton second law - Diff Eq problem
A 9kg object falls vertically downward. The magnitude of the force of air resistance is given by R = 6|v|. Take positive to be downward, Let y(0)= 0, v(0)=0, and let g = 10m/s^2
a. Write a differential equation for the velocity of the object and solve. b. What is the limiting velocity of this object. c. How far has the objecgt fallen when it reaches 80% of the limiting velocity
so far i know that ma = W - R W = weight and R being the air resistance
which basically might as well equal m(dv/dt) = mg-bv => dv/dt = g - (b/m)v
Do you know how to solve non-homogenous, first order, ODEs?
Nope, I haven't been taught how to "solve" any ODE yet
i know how to separate homogenous equations and then do IVP but that's about it
You have: \[\frac{dv}{dt}=g-\frac{b}{m}v \implies \frac{dv}{dt}=-\frac{b}{m}(v-\frac{gm}{b})\] \[\frac{dv}{v-\frac{mg}{b}}=-\frac{b}{m}dt \implies \ln \left| v-\frac{mg}{b} \right|=-\frac{b}{m}t+C\]
Yeah, here's what I don't understand. How does g - bv/m = -b/m(v-gm/b) Obviously she's factoring out a -b/m but where does that come from
Its just to make it simpler to integrate.
Ohhhhh, no i totally see what's going on now
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