Question

write the equation of the line parallel to the line 4x-6y=-1 and contains the x intercept of 3x-2y=12

Answer 1

slope = 2/3 , x-intercept = (4.0) ===> equation is y =(2/3) x+b ==> b=-8/3 ===> y=(2/3)x-(8/3)

Answer 2

Okay, first off, we need a line with the same slope as 4x-6y=-1
In slope-intercept form this becomes:
6y=4x+1
or
y=(2/3)x+(1/6)
So our slope is 2/3
Now we also need an x-intercept which is the same as the x-intercept of the line 3x-2y=12
Setting y=0, we solve for the x-int:
3x-2(0)=12
3x=12
x=4
So our x-int is the point (4,0).
We now have a point (4,0) and a slope (=2/3) which is all we need to describe a line. Point-slope form gives us our line:
y-0=(2/3)(x-4)
Rearranging, we get:
y=(2/3)x-(8/3)

Answer 3

agreed.

Answer 4

So, first thing's first: bust out your list of trig identities and find: \[1+\tan ^2x\]