The acceleration due to gravity on the moon is 1.62 m/s^2, approximately a sixth of the value on earth. For a given velocity V and a given angle theta, the ratio of the range of an ideal projectile on the moon to the range of the same projectile on earth Rmoon/Rearth will be?

Question

The acceleration due to gravity on the moon is 1.62 m/s^2, approximately a sixth of the value on earth.  For a given velocity V and a given angle theta, the ratio of the range of an ideal projectile on the moon to the range of the same projectile on earth Rmoon/Rearth will be?

anonymous · Answer

since nobody helped with the last one lol...figured try this one

anonymous · Answer

The answer is 1/6..
Is this physics or math?

anonymous · Answer

physics...i put in both sections

anonymous · Answer

it's multiple choice.... a. 2 b. 4 c. 6 d. 3 and e is 12

anonymous · Answer

so...don't think itll be 1/6

anonymous · Answer

This was how I did it... so projectile motion is just horizontal motion, and the formula for x (the distance) = 1/2at^2... 

If I divide Rmoon by Rearth = the time cancels out so it will be $$\left(\begin{matrix}1/2(1.62) \ 1/2(9.72)\end{matrix}\right)$$ = 1/6......

anonymous · Answer

it's multiple choice.... a. 2 b. 4 c. 6 d. 3 and e is 12

anonymous · Answer

Yeah, so I don't know... I was just showing you in case you wanted to know how I got my answer...

anonymous · Answer

if i actually just solve that i get 4....so i dont know now