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integral of [(2-3sin2x) divided by (cos2x)] dx
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use method of partial fractions to decompose it into components
sorry that was for your earlier question x^2/x+2
wow you don't even have to ask to integrate, it does it for you. click show steps and it is all worked out. enjoy! http://www.wolframalpha.com/input/?i=%282-3sin2x%29+divided+by+%28cos2x%29
I cant do this by just algebraic substitution...
2sec(2x)-3tan(2x) now integrate simply ln(sec2x+tan2x)-3/2lnsec2x+c
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