Question

(1-tan([theta])^(2))/sec([theta]) =1, sec([theta]) + 2sin([theta]) help me verify it

Answer 1

Something wrong there...?

Answer 2

YEAHHH SEMANGAT

Answer 3

no i have to show the steps tpo verify it to make both sides equal

Answer 4

This part

/sec([theta]) =1, sec([theta]) +

doesn't make sense.

Answer 5

the / is divided by

Answer 6

=1, sec([theta])

Please use equation editor or attach a pic.

Answer 7

\[1-\tan \Theta ^{2}\div \sec \theta = \sec \theta + 2\sin \theta\]

Answer 8

1-tan^2 = 1-(sec^2-1) = sec^2 +2

So then multiply through by sec and the rhs comes out to the same.