Question

can someone help me to prove that the dimensions of the electric field are: MLT^(-2)Q^(-1)

Answer 1

Electric field has dimensions of (Force/Unit Charge).
Force is Newton = mass*acceleration = kg.m/s^2 = MLT^(-2)
Charge is Coulomb = Q
Hence Electric field has dimensions MLT^(-2)/Q = MLT^(-2)Q^(-1)

Answer 2

e = f/q
f= m*a = MLT^-2
THUS E= MLT-^2 Q-^1