Question

log5(x+2)-log5 10=log5 100

Answer 1

Recall, that for any base, \[\log_a b - \log_a c = \log_a\dfrac{b}{c}\]Thus:\[\log_5 \dfrac{x+2}{10} = \log_5 100\]\[\dfrac{x+2}{10}=100\]\[x = 998\]

Answer 2

log5 x+2)/10 = log5 100
(x+2)/10 = 100
x + 2 = 1000
x = 998